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# P6 PSLE Maths (Area)

Updated: May 18, 2020

**In the figure above, Rectangles ACLN and FGHI are the same. Squares CDEF and IJKL are the same. AC= 2CL. B and M are midpoints for AC and LN, respectively. O is the midpoint of ABMN. Perimeter of CFIL = 12cm. Total area of ACLN, FGHI, IJKL and CDEF = 72 square cm.Express the area of CBOL as a fraction of the whole figure.**

**Answer:**

➡️NOL= 0.25 ACLN ➡️ABN= 0.25 ACLN ➡️CBOL=1-0.25-0.25=0.5 of ACLN ➡️ACLN+CDEF= 36 square cm ➡️CF+CL= 12➗2=6 ➡️ Try CF= 1 Hence CL=5 AC=10 Area of ACLN=AC x CL=10 x 5=50 Area of CDEF= 1 Total area of ACLN + CDEF= 51 square cm (rejected) ➡️ Try CF=2 Hence CL= 4 AC= 8 Area of ACLN=AC x CL=4x 8= 32 Area of CDEF= 2x2 =4 Total area of ACLN + CDEF= 36 square cm ➡️Hence CL=4 AC=8 CF=2 ➡️Total area of figure= 2(4x8) + 2x4 + 2(2x2)= 80 square cm ➡️Area of CBOL= 0.5 of ACLN = 0.5 x 8x 4= 16 square cm ➡️Fraction of CBOL of the whole figure= 16/80= 9/40

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