- The Math Tutor SG

# P6 PSLE Maths (Distance, Speed, Time)

Updated: May 18

**Car P left for Town Z from Town Y at 12.15pm. At 2.30pm, Car Q left Town Z for Town Y. Car P takes 73/6 hrs to reach Town Z. Car Q takes 73/8 hrs to reach Town Y. Car P would have travelled 75 km more than Car Q when both of them met. **

**a)What was the distance between the 2 towns?**

**b) What was the speed of Car P and Car Q, respectively?**

**Answer:**

Car P left for Town Z from Town Y at 12.15pm. At 2.30pm, Car Q left Town Z for Town Y. Car P takes 73/6 hrs to reach Town Z. Car Q takes 73/8 hrs to reach Town Y. Car P would have travelled 75 km more than Car Q when both of them met. a)What was the distance between the 2 towns? b) What was the speed of Car P and Car Q, respectively? ➡️In 1hr, Car P travelled = 1 / (73/6) = 6/73 of YZ Car Q travelled = 1 / (73/8) = 8/73 of ZY Total distance covered in 1hr= 14/73 ➡️From 12.15 pm to 2.30pm Total no of hrs= 2.25hrs

Before Car Q set off for Town Y,Car P would have travelled = 2.25 x (6/73)= 27/146 of YZ (Car P) At 2.30pm, Distance from Town Z= 1- (27/146)= 119/146 ➡️Time taken to meet from 2.30pm onwards= (119/146) ➗ (14/73) = 4.25hrs ➡️Total time Car P would have travelled before meeting Car Q = 4.25 + 2.25 = 6.5hrs ➡️Total time for Car Q would have travelled before meeting Car P = 4.25hrs ➡️(Car Q)Distance Travelled in 4.25hrs = 4.25 x (8/73) = 34/73 ➡️(car P) Distance travelled in 6.5hrs= 6.5x (6/73)= 39/73 ➡️Car P would have travelled a more distance of = (39/73) - (34/73) = 5/73 In other words 5u= 75km 1u= 15km 73u= 1095km (a) YZ= 1095km (b) Speed of Car P= 1095/(73/6) = 90km/h Speed of Car Q= 1095/(73/8) =120km/h

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